Substitution Method for Linear Equations- Practice Problems

What Is the Substitution Method?

The substitution method is a way to solve systems of linear equations. You solve one equation for one variable, then plug that expression into the other equation. That's it. Nothing fancy.

It works best when one variable has a coefficient of 1 or -1. If both variables have ugly coefficients, the elimination method is usually faster.

How to Use Substitution (The Actual Steps)

Here's the process:

Let's walk through a real example.

Example 1: Basic Substitution

Problem: Solve the system
y = 2x + 3
3x + y = 11

Step 1: The first equation already has y isolated. Use it.

Step 2: Substitute 2x + 3 for y in the second equation.

3x + (2x + 3) = 11

Step 3: Solve for x.

5x + 3 = 11
5x = 8
x = 8/5 = 1.6

Step 4: Plug x back into y = 2x + 3.

y = 2(1.6) + 3
y = 3.2 + 3
y = 6.2

Solution: (1.6, 6.2)

Example 2: Neither Variable Is Isolated

Problem: Solve the system
2x + y = 7
x - 3y = -2

Step 1: Solve the first equation for y.

y = 7 - 2x

Step 2: Substitute into the second equation.

x - 3(7 - 2x) = -2
x - 21 + 6x = -2
7x - 21 = -2
7x = 19
x = 19/7

Step 3: Find y.

y = 7 - 2(19/7)
y = 7 - 38/7
y = 49/7 - 38/7
y = 11/7

Solution: (19/7, 11/7)

Practice Problems

Try these before checking the solutions. No peeking.

Problem 1

Solve the system:
y = x - 4
2x + y = 10

Solution:
Substitute x - 4 for y:
2x + (x - 4) = 10
3x - 4 = 10
3x = 14
x = 14/3

y = 14/3 - 4 = 14/3 - 12/3 = 2/3

Answer: (14/3, 2/3)

Problem 2

Solve the system:
3x - 2y = 8
x + 4y = -6

Solution:
Solve x + 4y = -6 for x:
x = -6 - 4y

Substitute into 3x - 2y = 8:
3(-6 - 4y) - 2y = 8
-18 - 12y - 2y = 8
-18 - 14y = 8
-14y = 26
y = -26/14 = -13/7

Find x:
x = -6 - 4(-13/7)
x = -6 + 52/7
x = -42/7 + 52/7
x = 10/7

Answer: (10/7, -13/7)

Problem 3

Solve the system:
5x + y = 3
3x - 2y = -1

Solution:
Solve for y: y = 3 - 5x

Substitute:
3x - 2(3 - 5x) = -1
3x - 6 + 10x = -1
13x - 6 = -1
13x = 5
x = 5/13

Find y:
y = 3 - 5(5/13)
y = 3 - 25/13
y = 39/13 - 25/13
y = 14/13

Answer: (5/13, 14/13)

Problem 4

Solve the system:
y = -2x + 1
4x + 2y = 2

Solution:
Substitute -2x + 1 for y:
4x + 2(-2x + 1) = 2
4x - 4x + 2 = 2
2 = 2

This is true. The system has infinitely many solutions—the equations are equivalent.

Answer: Infinitely many solutions (dependent system)

Problem 5

Solve the system:
y = 3x - 5
6x - 2y = 10

Solution:
Substitute 3x - 5 for y:
6x - 2(3x - 5) = 10
6x - 6x + 10 = 10
10 = 10

Same result. Infinitely many solutions again.

Answer: Infinitely many solutions (dependent system)

Problem 6

Solve the system:
x - 2y = 3
2x - 4y = 5

Solution:
Solve x - 2y = 3 for x: x = 3 + 2y

Substitute:
2(3 + 2y) - 4y = 5
6 + 4y - 4y = 5
6 = 5

Contradiction. No solution exists.

Answer: No solution (inconsistent system)

Substitution vs Elimination: Which to Use?

Here's a quick comparison:

Method Best When Messy When
Substitution One variable has coefficient 1 or -1 All coefficients are large numbers
Elimination Variables line up easily for cancellation You'd need to multiply everything by fractions

Most textbooks let you choose. Pick whatever creates less work.

Common Mistakes to Avoid

Quick Reference Checklist

That's substitution. Practice the problems above until you can do them without checking the solutions. The process is mechanical—once you see the pattern, you won't overthink it.