How to Eliminate Exponents Using Natural Log
Why Natural Log is Your Exponent Eraser
When you see an equation with a variable trapped inside an exponent, your first instinct might be to panic. Don't. Natural log (ln) exists precisely for this situation.
The natural log is the inverse of the exponential function ex. That inverse relationship is what makes it so powerful. Whatever an exponent does, ln undoes it.
Here's the core rule you need to memorize:
If ln(ex) = x and eln(x) = x
That's it. Everything else follows from this.
When to Use This Method
You need natural log when your variable is in the exponent position and you can't isolate it any other way. Common scenarios:
- Solving exponential equations like 52x = 50
- Equations where the base can't be rewritten as a common power
- Real-world growth and decay problems
- Any situation requiring you to "pull down" an exponent
The Step-by-Step Process
Step 1: Isolate the Exponential Term
Get the term with the exponent by itself on one side. Use basic algebra—add, subtract, divide, or multiply both sides until the exponential expression stands alone.
Step 2: Take the Natural Log of Both Sides
Apply ln to everything. This isn't cheating—it's using the properties of logarithms. Whatever you do to one side, you must do to the other.
Step 3: Pull the Exponent Down Using Log Properties
Remember: ln(ab) = b · ln(a)
Your exponent becomes a coefficient. The variable that was trapped upstairs is now a regular multiplier in front of ln(base).
Step 4: Solve for the Variable
Now you have a normal algebraic equation. Divide, multiply, or isolate as needed. The exponent is gone.
Practical Examples
Example 1: Basic Case
Solve: 3x = 20
Both sides are already isolated. Take ln of both sides:
ln(3x) = ln(20)
Pull down the exponent:
x · ln(3) = ln(20)
Solve:
x = ln(20) / ln(3)
Throw this into a calculator: x ≈ 2.73
Example 2: Variable in the Exponent (More Complex)
Solve: e2x = 15
Take ln of both sides:
ln(e2x) = ln(15)
The ln and e cancel out, leaving:
2x = ln(15)
Divide by 2:
x = ln(15) / 2 ≈ 1.35
Example 3: Coefficient in the Exponent
Solve: 43x+1 = 100
Take ln of both sides:
ln(43x+1) = ln(100)
Pull down the exponent:
(3x + 1) · ln(4) = ln(100)
Expand:
3x · ln(4) + ln(4) = ln(100)
Isolate the term with x:
3x · ln(4) = ln(100) - ln(4)
Solve:
x = [ln(100) - ln(4)] / [3 · ln(4)]
x ≈ 1.07
Natural Log vs. Common Log: Does It Matter?
Short answer: no.
You can use ln (base e) or log (base 10). The base cancels out in the final division. Here's proof:
| Property | Natural Log (ln) | Common Log (log) |
|---|---|---|
| Base | e ≈ 2.718 | 10 |
| Formula | x = ln(y) / ln(base) | x = log(y) / log(base) |
| Result | Same as common log | Same as natural log |
Use whatever log your calculator gives you easily. The math works out identical.
Common Mistakes That Will Cost You
- Forgetting to take the log of both sides. You can't solve it if you only log one side.
- Not isolating the exponential first. Log both sides of the wrong equation and you'll chase your tail.
- Dropping the exponent incorrectly. Remember—ln(ab) = b·ln(a), not b·a.
- Rounding too early. Keep full precision until the final answer, or errors compound.
Getting Started: Your Quick Checklist
Before you solve any exponential equation:
- Can I rewrite the base as a power of something? If yes, try that first.
- If not, is the exponential term isolated? If not, isolate it.
- Take ln of both sides.
- Use the power rule to bring the exponent down.
- Solve the resulting linear equation.
- Check your answer by plugging it back in.
When Natural Log Won't Help
This method assumes your variable is in the exponent position. If the variable is in the base (like x5 = 32), you need different tools—roots, factoring, or other algebraic methods.
Natural log specifically handles variable-in-exponent problems. That's its lane.
The Bottom Line
Eliminating exponents with natural log is a three-step process: isolate, take ln, solve. The math is straightforward once you internalize that ln and e cancel each other out.
Practice the examples above. The first few times feel clunky. After a few problems, it becomes automatic. There's no trick here—just algebra with a specific purpose.