Solve Absolute Value Equations- Methods and Examples

What Absolute Value Equations Actually Are

An absolute value equation contains a variable wrapped in absolute value bars, like |x - 3| = 7. The absolute value of a number is its distance from zero on the number line. Distance is always positive, so |−5| = 5 and |5| = 5.

The equation |x| = a means x is a units from zero. That gives you two possible solutions: x = a or x = −a. This is the foundation for solving every absolute value equation you'll encounter.

The Core Rule You Need to Memorize

For any equation |A| = B where B ≥ 0:

That's it. Everything else is applying this rule correctly.

Method 1: The Two-Case Approach

Break the equation into two separate equations based on the definition of absolute value.

Example: Solve |x - 3| = 7

Case 1: x − 3 = 7 → x = 10

Case 2: x − 3 = −7 → x = −4

Check both: |10 − 3| = 7 ✓ and |−4 − 3| = 7 ✓

Both solutions check out. Your answer is x = 10 or x = −4.

Example: Solve |2x + 1| = 5

Case 1: 2x + 1 = 5 → 2x = 4 → x = 2

Case 2: 2x + 1 = −5 → 2x = −6 → x = −3

Verify: |2(2) + 1| = 5 ✓ and |2(−3) + 1| = 5 ✓

Solutions: x = 2 or x = −3

Method 2: The Graphical Method

Rewrite the equation so the absolute value is isolated on one side. Then graph the left side (a V-shaped graph) and the right side (a horizontal line). The intersection points are your solutions.

For |x − 2| = 4, graph y = |x − 2| and y = 4. The V-shape crosses y = 4 at x = −2 and x = 6.

This method works great when you're asked to solve "using a graph" or when you want a visual check of your algebraic answer.

Method 3: Absolute Value Equals Zero

When |A| = 0, there's only one solution: A = 0. No need for two cases.

Example: Solve |3x + 6| = 0

3x + 6 = 0 → 3x = −6 → x = −2

Only one solution. |3(−2) + 6| = |−6 + 6| = 0 ✓

No Solution Situations

If the right side is negative, there's no solution. Absolute value cannot equal a negative number.

Example: |x + 4| = −3

No solution. The left side is always ≥ 0, but the right side is −3. Impossible.

Example: |2x − 1| = −5

No solution. Same reason.

Equations with Variables on Both Sides

Sometimes you'll get |A| = B where B also contains the variable. You still use two cases, but you'll need to solve each inequality or equation carefully.

Example: |x + 2| = 3x − 4

Case 1: x + 2 = 3x − 4 → 2 + 4 = 3x − x → 6 = 2x → x = 3

Case 2: x + 2 = −(3x − 4) → x + 2 = −3x + 4 → x + 3x = 4 − 2 → 4x = 2 → x = 0.5

Critical check: The right side 3x − 4 must be ≥ 0 for the original equation to make sense.

For x = 3: 3(3) − 4 = 5 ≥ 0 ✓

For x = 0.5: 3(0.5) − 4 = −2.5 < 0 ✗

Only x = 3 is valid. x = 0.5 gets discarded.

Comparing the Three Methods

MethodBest ForProsCons
Two-Case AlgebraMost standard problemsAlways works, straightforwardCan forget to check solutions
GraphicalVisual learners, checking workShows all solutions at onceLess precise without technology
Zero CaseEquations equal to zeroFast, one solution onlyLimited to specific cases

How to Solve Any Absolute Value Equation

Step 1: Isolate the absolute value expression on one side. Get |A| alone.

Step 2: Identify what B equals on the other side.

Step 3: If B < 0 → No solution. If B = 0 → One solution (A = 0). If B > 0 → Two cases.

Step 4: For two cases, write A = B and A = −B. Solve each.

Step 5: Check every solution in the original equation. Discard any that don't work.

Common Mistakes That Will Cost You Points

Practice Problems

1. |x − 5| = 3

Solutions: x = 8 or x = 2

2. |4x + 2| = 10

Solutions: x = 2 or x = −3

3. |x/2 − 3| = 5

Solutions: x = 16 or x = −4

4. |x² − 9| = 0

Solution: x = 3 or x = −3

Absolute value equations aren't complicated once you internalize the two-case rule. Practice setting them up, solve both cases, and always verify your answers. That's the entire game.