Log Equation- Solving Logarithmic Equations
What Log Equations Actually Are
A log equation is any equation where the variable sits inside a logarithm. That's it. If you see log, ln, or any variable trapped in a logarithm, you're dealing with a log equation.
The goal is always the same: isolate the variable and solve. But the process trips up most students because they forget the core relationship.
Remember this forever:
logb(x) = y is the same as by = x
This one conversion is the backbone of every log equation you'll ever solve. Everything else is just manipulation around this relationship.
Essential Logarithm Rules You Need
Before touching any equation, these rules must be automatic. If you're hunting for them mid-problem, you're already lost.
- Product Rule: logb(MN) = logbM + logbN
- Quotient Rule: logb(M/N) = logbM - logbN
- Power Rule: logb(Mp) = p ยท logbM
- Change of Base: logbM = logkM / logkb (any base k)
- logb1 = 0 (anything to the power of 0 is 1)
- logbb = 1
Most log equation errors come from forgetting these or applying them backwards. Keep them straight.
How to Solve Log Equations
Here's the process. No fluff.
Step 1: Identify the Domain
Logarithms only accept positive arguments. Before you do anything else, find what x cannot be.
If your equation has log(x - 3), then x - 3 > 0, so x > 3. That's your domain restriction. Solutions outside this range are invalid, no matter how clean the algebra looks.
Step 2: Combine Logs If Needed
Most equations have logs on both sides. Use the rules above to combine them into a single log expression per side.
Example:
log(x) + log(3) = log(6)
Combine left side: log(3x) = log(6)
Step 3: Drop the Logs
Once you have log(something) = log(something else), drop both logs. They're equal only if the somethings are equal.
3x = 6
Step 4: Solve the Resulting Equation
Now it's basic algebra. Solve for x.
3x = 6 โ x = 2
Step 5: Check Your Answer
Plug x = 2 back into your original equation. Does it work? If not, discard it. Domain restrictions apply.
log(2) + log(3) = log(6) โ
Common Log Equation Patterns
Pattern 1: Variable Inside a Single Log
log2(x + 5) = 4
Convert to exponential form: 24 = x + 5
16 = x + 5
x = 11
Check: log2(16) = 4 โ
Pattern 2: Logs on Both Sides
log3(x + 1) = log3(2x - 4)
Drop the logs: x + 1 = 2x - 4
1 + 4 = 2x - x
x = 5
Check domain: x + 1 > 0 and 2x - 4 > 0. Both true when x = 5. โ
Pattern 3: Variable in the Base
logx(8) = 3
Convert: x3 = 8
x = 2
Domain note: base x must be positive and โ 1. x = 2 works.
Pattern 4: Natural Log Equations
ln(x) + ln(x - 2) = ln(8)
Combine left: ln(x(x - 2)) = ln(8)
Drop ln: x(x - 2) = 8
x2 - 2x - 8 = 0
(x - 4)(x + 2) = 0
x = 4 or x = -2
Check domain: ln requires positive arguments. x = -2 fails. Only x = 4 works.
Natural Log vs. Log Base 10
ln means loge โ base e (approximately 2.718).
log without a subscript usually means log10.
Solving works the same way for both. The rules don't change. Only the base does.
Mistakes That Will Cost You
- Dropping logs without matching bases: You can only drop logs when both sides are single logs. log(x) = 3 + log(5) doesn't let you drop anything.
- Ignoring domain restrictions: This is how you get extraneous solutions. Always check.
- Distributing inside a log: log(x + y) โ log(x) + log(y). That's backwards. You combine, not distribute.
- Forgetting to convert to exponential form: If the variable is in the exponent position of the converted form, you need to use logs to solve. If the variable is inside the log, you don't.
- Mixing up product and quotient rules: Multiplying inside becomes addition outside. Dividing inside becomes subtraction outside. Keep them straight.
Quick Reference: Log Rules at a Glance
| Rule Name | Log Form | Expanded Form |
|---|---|---|
| Product Rule | logb(MN) | logbM + logbN |
| Quotient Rule | logb(M/N) | logbM - logbN |
| Power Rule | logb(Mp) | p ยท logbM |
| Change of Base | logbM | logkM / logkb |
| Zero Property | logb1 | 0 |
| Identity | logbb | 1 |
Practice: Solve These
Try these before checking answers below.
1. log5(x + 4) = 2
2. log2(x) + log2(x - 2) = 3
3. ln(2x) = 4
Answers
1. 52 = x + 4 โ 25 = x + 4 โ x = 21
2. Combine: log2(x(x - 2)) = 3 โ x2 - 2x = 8 โ x2 - 2x - 8 = 0 โ (x - 4)(x + 2) = 0 โ x = 4 (x = -2 fails domain)
3. e4 = 2x โ x = e4/2 โ 27.3
The Bottom Line
Log equations aren't hard. They're mechanical. Combine logs, drop them, solve the leftover equation, check your work. That's the entire process.
The mistakes aren't conceptual โ they're procedural. You know the rules. Apply them correctly. Check your answers. That's it.