Inverse Trigonometric Functions- Sin, Cos, Tan Inverses
What Inverse Trigonometric Functions Actually Are
Inverse trig functions sound complicated until you realize they're just asking a simple question: "If I know the ratio, what was the angle?"
Regular trig functions take an angle and give you a ratio. Inverse trig functions do the opposite—they take a ratio and give you the angle. That's it. That's the whole concept.
Mathematicians denote them as arcsin, arccos, and arctan. Your calculator shows them as sin⁻¹, cos⁻¹, and tan⁻¹. The notation looks similar to exponents but means something completely different.
The Six Inverse Trig Functions
Each of the three main trig functions has an inverse. Here's what you need to know:
Arcsine (sin⁻¹ or arcsin)
Inverse of sine. Takes a sine value between -1 and 1, returns an angle.
Problem: sine isn't one-to-one. Multiple angles share the same sine value. So arcsin is restricted to angles between -90° and 90° (or -π/2 to π/2 radians).
Arccosine (cos⁻¹ or arccos)
Inverse of cosine. Takes a cosine value between -1 and 1, returns an angle.
Range is restricted to 0° to 180° (or 0 to π radians) because cosine has the same one-to-one problem.
Arctangent (tan⁻¹ or arctan)
Inverse of tangent. Takes any real number, returns an angle.
Range is -90° to 90° (or -π/2 to π/2 radians), excluding the asymptotes where tangent is undefined.
The Other Three
- Arccosecant (csc⁻¹) — inverse of cosecant
- Arcsecant (sec⁻¹) — inverse of secant
- Arccotangent (cot⁻¹) — inverse of cotangent
These come up less often but follow the same logic.
Domain and Range at a Glance
This table shows what values each function accepts and what angles it returns:
| Function | Domain (input) | Range (output) |
|---|---|---|
| arcsin(x) | [-1, 1] | [-π/2, π/2] or [-90°, 90°] |
| arccos(x) | [-1, 1] | [0, π] or [0°, 180°] |
| arctan(x) | All real numbers | (-π/2, π/2) or (-90°, 90°) |
| arccsc(x) | (-∞, -1] ∪ [1, ∞) | [-π/2, 0) ∪ (0, π/2] |
| arcsec(x) | (-∞, -1] ∪ [1, ∞) | [0, π/2) ∪ (π/2, π] |
| arccot(x) | All real numbers | (0, π) or (0°, 180°) |
Key Properties You Can't Ignore
Composition Rules
When you nest a trig function with its inverse, they mostly cancel out—but not always perfectly:
- sin(sin⁻¹(x)) = x — only when x is in the domain [-1, 1]
- sin⁻¹(sin(x)) = x — only when x is in the restricted range [-π/2, π/2]
That second one trips people up constantly. If x is outside the principal range, the functions don't simply cancel. You have to account for which quadrant the angle actually lands in.
Complementary Relationships
Arcsine and arccosine have a clean relationship:
sin⁻¹(x) + cos⁻¹(x) = π/2 (or 90°)
This holds for any valid x. Useful when you need to convert between the two.
Arctangent and Arccotangent
tan⁻¹(x) + cot⁻¹(x) = π/2 (or 90°)
Same pattern, different functions.
How to Actually Use These
Getting Started
Example 1: Basic angle finding
Question: Find sin⁻¹(0.5)
Step 1: Ask yourself what angle has sine = 0.5
Step 2: Recall or calculate—it's 30° or π/6 radians
Step 3: Verify it's within the principal range [-90°, 90°]—yes, it is
Answer: sin⁻¹(0.5) = π/6 (or 30°)
Example 2: Arccos calculation
Question: Find arccos(-0.866)
Step 1: What angle has cosine = -0.866?
Step 2: That's approximately 150° or 5π/6 radians
Step 3: Check the range—arccos returns [0°, 180°], and 150° fits
Answer: arccos(-0.866) ≈ 5π/6
Example 3: Arctan of a negative number
Question: Find arctan(-1)
Step 1: What angle has tangent = -1?
Step 2: That's -45° or -π/4 radians
Step 3: Check the range—arctan returns (-90°, 90°), and -45° fits
Answer: arctan(-1) = -π/4
Solving Triangles
Inverse trig functions are essential in non-right triangles when you know side ratios but need angles.
Example: In a triangle with sides a=3, b=4, c=5, find angle A.
Step 1: Use Law of Cosines: cos(A) = (b² + c² - a²) / (2bc)
Step 2: Plug in: cos(A) = (16 + 25 - 9) / (2 × 4 × 5) = 32/40 = 0.8
Step 3: Take arccos: A = cos⁻¹(0.8) ≈ 36.87° or ≈ 0.644 radians
Common Mistakes That Ruin Your Answers
- Forgetting the range restriction. sin⁻¹(0.5) isn't 150°. It's only 30° in the principal value. If you need 150°, you have to adjust based on context.
- Confusing notation. sin⁻¹(x) means arcsine, not 1/sin(x). The reciprocal is csc(x), not sin⁻¹(x).
- Trying to take arcsin of 2. Impossible. Sine values only go from -1 to 1. The function is undefined outside that.
- Ignoring radians vs degrees. Most math courses use radians. Your calculator might default to degrees. Check your settings.
- Assuming symmetry. sin⁻¹(-x) = -sin⁻¹(x) works for arcsine and arctangent. It does NOT work for arccos. arccos(-x) = π - arccos(x).
Where Inverse Trig Functions Actually Appear
These aren't just textbook exercises. Inverse trig functions show up in:
- Physics — calculating angles of incidence and reflection, projectile motion trajectories
- Engineering — analyzing forces on ramps, determining gear angles
- Computer graphics — rotating objects, calculating angles between vectors
- Signal processing — Fourier transforms, phase calculations
- Navigation — GPS calculations, bearing measurements
If you're doing anything with angles derived from measurements, you're probably using inverse trig functions whether you realize it or not.
Quick Reference for the Road
- Inverse trig functions answer: "What angle gives me this ratio?"
- sin⁻¹: domain [-1,1], range [-90°, 90°]
- cos⁻¹: domain [-1,1], range [0°, 180°]
- tan⁻¹: domain all real, range (-90°, 90°)
- sin(sin⁻¹(x)) = x only when x is valid
- sin⁻¹(sin(x)) = x only when x is in principal range
- sin⁻¹(x) + cos⁻¹(x) = 90° always