Sigma Notation with Left Endpoint- On Subinterval Approximation
What Sigma Notation Actually Is
Sigma notation is just a compact way to write long sums. Instead of writing x₁ + x₂ + x₃ + ... + x₁₀₀, you write Σ with the starting point, ending point, and what you're adding.
The symbol Σ (Greek letter sigma) means "add up everything that follows." It's not complicated. It's shorthand.
Why Left Endpoint Approximation Matters
When you can't find an exact integral, you approximate it using rectangles. The left endpoint rule builds rectangles using the left side of each subinterval as the rectangle's height.
This is the most intuitive approach. You look at each small chunk of the x-axis, grab the function value on its left edge, and draw a rectangle there.
The General Formula
For approximating ∫f(x)dx from a to b using n subintervals:
Δx = (b - a) / n
Approximation = Σ f(xᵢ) Δx, where i goes from 0 to n-1
The left endpoint of subinterval i is xᵢ = a + i·Δx
You evaluate f at each left endpoint, multiply by the width, and sum everything up.
Step-by-Step: How To Calculate Left Endpoint Approximation
Step 1: Find Δx
Divide your interval width by the number of rectangles.
Δx = (upper bound - lower bound) / number of subintervals
Step 2: Identify the left endpoints
Your x-values are: x₀, x₁, x₂, ... xₙ₋₁
Each one is: xᵢ = a + i·Δx
You stop at n-1 because the leftmost point of the last rectangle is the (n-1)th point.
Step 3: Evaluate the function at each left endpoint
Plug every xᵢ into f(x). Write down each result.
Step 4: Multiply by Δx and sum
Take each f(xᵢ), multiply by Δx, add them all together. That's your approximation.
Worked Example
Problem: Approximate ∫x² dx from 0 to 2 using n=4 subintervals with the left endpoint rule.
Step 1: Calculate Δx
Δx = (2 - 0) / 4 = 0.5
Step 2: Find left endpoints
x₀ = 0 + 0·0.5 = 0
x₁ = 0 + 1·0.5 = 0.5
x₂ = 0 + 2·0.5 = 1
x₃ = 0 + 3·0.5 = 1.5
Step 3: Evaluate f(x) = x² at each point
f(0) = 0² = 0
f(0.5) = 0.5² = 0.25
f(1) = 1² = 1
f(1.5) = 1.5² = 2.25
Step 4: Multiply and sum
Approximation = [0 + 0.25 + 1 + 2.25] × 0.5
Approximation = 3.5 × 0.5 = 1.75
The actual value is 8/3 ≈ 2.67, so our left endpoint approximation gives us an underestimate. More on that shortly.
Left vs. Right vs. Midpoint: The Comparison
Here is how left endpoint stacks up against other rectangle methods:
| Method | Rectangle Height | Best When | Typical Error |
|---|---|---|---|
| Left Endpoint | Left side of subinterval | Function is increasing | Underestimates if rising |
| Right Endpoint | Right side of subinterval | Function is increasing | Overestimates if rising |
| Midpoint Rule | Center of subinterval | Any function | Usually smallest error |
| Trapezoidal Rule | Average of both endpoints | Curved functions | Good all-around accuracy |
The left endpoint rule consistently underestimates increasing functions and overestimates decreasing functions. That's not a bug—it's information you can use.
When Left Endpoint Makes Sense
Left endpoint approximation is useful when:
- You want the simplest possible method to implement in code
- The function is strictly increasing and you need a conservative estimate
- You're doing quick preliminary calculations
- You want to pair with right endpoint to bound the true value
The left and right endpoint errors have opposite signs. If you average them, you get something close to the trapezoidal rule. If you average them and compare to the actual value, you know your error is bounded.
Common Mistakes
Using n points instead of n-1: With n subintervals, you only evaluate at n left endpoints, not n+1. The last left endpoint is xₙ₋₁, not xₙ.
Forgetting to multiply by Δx: The function values alone aren't the area. You must multiply each by the subinterval width before summing.
Confusing the formula for xᵢ: Left endpoints use xᵢ = a + i·Δx. Right endpoints use xᵢ = a + (i+1)·Δx. Different starting index.
Writing It in Sigma Notation
The full left endpoint approximation in sigma notation looks like this:
∫f(x)dx ≈ Σ f(a + i·Δx) · Δx where i = 0 to n-1
That's it. You can leave it in this form or expand it fully:
≈ [f(a) + f(a+Δx) + f(a+2Δx) + ... + f(a+(n-1)Δx)] · Δx