Logarithmic Equations- Solving Methods and Examples
What Is a Logarithmic Equation?
A logarithmic equation contains a logarithm with an unknown variable inside it. The goal is always the same: find the value of that variable that makes the equation true.
These equations show up in science, engineering, finance, and computer science. If you're studying math past algebra, you'll need to solve them. Period.
The basic form looks like this:
logb(x) = y
This means "b raised to what power gives you x?" The answer is y. That's it.
Core Logarithm Properties You Must Know
You can't solve these equations without the properties. Memorize them. I don't care how you do itβflashcards, repetition, tattoo them on your handβbut know these cold.
Product Rule
logb(MN) = logb(M) + logb(N)
Quotient Rule
logb(M/N) = logb(M) β logb(N)
Power Rule
logb(Mp) = p Β· logb(M)
Change of Base Formula
logb(x) = loga(x) / loga(b)
This one is useful when you need to convert between bases or use a calculator that only has log10.
How to Solve Logarithmic Equations
Here's the practical approach. Three main methods exist, and you pick based on what the equation looks like.
Method 1: Convert to Exponential Form
This works when you have a single logarithm on one side.
Steps:
- Identify the base
- Rewrite the logarithm as an exponential equation
- Solve the resulting equation
- Check your answer in the original equation
Method 2: Use Logarithm Properties First
When multiple logarithms appear, combine or simplify them using the rules above until you get a single log expression.
Method 3: Exponentiate Both Sides
When the equation has logs on both sides, raise both sides to the power of the base to eliminate the logarithms.
Solved Examples
Example 1: Basic Single Logarithm
Solve: log3(x) = 4
Convert to exponential form:
34 = x
3 Γ 3 Γ 3 Γ 3 = 81
Answer: x = 81
Check: log3(81) = 4 β
Example 2: Logarithm with Addition
Solve: log2(x) + log2(x β 2) = 3
Use the product rule to combine:
log2(x(x β 2)) = 3
log2(x2 β 2x) = 3
Convert to exponential:
x2 β 2x = 23
x2 β 2x = 8
x2 β 2x β 8 = 0
Factor:
(x β 4)(x + 2) = 0
x = 4 or x = β2
Check domain restrictions: The argument of a logarithm must be positive. x = β2 gives log2(β2), which doesn't exist.
Answer: x = 4 only
Example 3: Natural Logarithm Equation
Solve: ln(x) + ln(x β 3) = ln(10)
Combine the left side using the product rule:
ln(x(x β 3)) = ln(10)
Since ln(a) = ln(b) means a = b:
x(x β 3) = 10
x2 β 3x = 10
x2 β 3x β 10 = 0
(x β 5)(x + 2) = 0
x = 5 or x = β2
Check: x = 5 works. x = β2 doesn't (negative argument for ln).
Answer: x = 5
Example 4: Logs on Both Sides
Solve: log5(x + 1) = log5(3x β 1)
When bases match, set arguments equal:
x + 1 = 3x β 1
2 = 2x
x = 1
Check: log5(2) = log5(2) β
Answer: x = 1
Example 5: Using Change of Base
Solve: log2(x) = log10(7)
Convert log10(7) to base 2 using change of base:
log10(7) = ln(7)/ln(2)
Or just use a calculator to get approximately 0.845:
log2(x) β 0.845
Convert to exponential:
x = 20.845
x β 1.79
Answer: x β 1.79
Common Mistakes That Will Sink You
- Ignoring domain restrictions: Logarithms only accept positive arguments. Always check that your solution makes the argument positive.
- Forgetting to check solutions: Extraneous solutions appear when you manipulate equations. Plug answers back into the original every time.
- Mixing up log rules: Product rule adds, quotient rule subtracts. Students mix these up constantly.
- Assuming both solutions work: In equations with multiple logs, often only one solution survives the domain check.
Quick Reference: Solving Methods
| Equation Type | Best Method | Key Step |
|---|---|---|
| logb(x) = number | Convert to exponential | x = bnumber |
| Sum or difference of logs | Use log properties first | Combine into single log |
| logb(f(x)) = logb(g(x)) | Set arguments equal | f(x) = g(x) |
| log with different bases | Change of base | Convert to common base |
| Variable in exponent and log | Use exponentiation | Raise both sides to base power |
Practice Problems
Try these before checking answers:
- log4(x) = 3
- log2(x + 5) = 6
- log(x) + log(x β 3) = 1
- ln(x2) = 4
- log3(x) = log3(2x β 9)
Answers:
- x = 64
- x = 59
- x = 5 (x = β2 rejected)
- x = Β±e2 β Β±7.39 (x = βe2 rejected by domain)
- x = 9 (x = 0 rejected)
The Bottom Line
Solving logarithmic equations comes down to three things: knowing your log properties, converting to exponential form when needed, and checking every solution against domain restrictions. That's it.
Don't overthink this. Practice twenty problems and you'll have it locked down.