Energy Conservation- Practice Problems and Solutions
What Energy Conservation Actually Means
Energy conservation isn't some abstract principle your teacher invented to torture you. It's a hard rule: energy cannot be created or destroyed — only converted from one form to another. That's it. Everything else in physics flows from that simple statement.
In mechanics problems, you're usually tracking the conversion between kinetic energy (KE = ½mv²) and gravitational potential energy (PE = mgh). Friction complicates things by converting mechanical energy into thermal energy, but the total energy of a closed system stays constant.
The Core Equation You Need
For most practice problems, you'll use this relationship:
KE₁ + PE₁ = KE₂ + PE₂
Or, if friction is involved:
KE₁ + PE₁ = KE₂ + PE₂ + W(friction)
Where W(friction) = f × d (force times distance).
Energy Types at a Glance
| Energy Type | Formula | Unit |
|---|---|---|
| Kinetic Energy | KE = ½mv² | Joules (J) |
| Gravitational PE | PE = mgh | Joules (J) |
| Elastic PE | PE = ½kx² | Joules (J) |
| Work done | W = Fd cos(θ) | Joules (J) |
Practice Problem #1: The Falling Object
Problem: A 2 kg ball drops from rest at height h = 10 m. Find its speed just before hitting the ground. Ignore air resistance.
Solution:
Initial state: ball at rest (v = 0), height h = 10 m
Final state: just before impact (height = 0)
Apply conservation of energy:
Initial PE = Final KE
mgh = ½mv²
Solve for v:
v² = 2gh
v² = 2(9.8)(10)
v² = 196
v = 14 m/s
That's your answer. No complicated kinematics needed. One equation, done.
Practice Problem #2: The Roller Coaster
Problem: A cart starts at rest at height 25 m. It rolls down a frictionless track. What is its speed at the bottom?
Solution:
Same setup as before. All potential energy converts to kinetic energy.
mgh = ½mv²
v = √(2gh)
v = √(2 × 9.8 × 25)
v = √490
v = 22.1 m/s
The mass cancels out completely. Every object falling from 25 m hits the bottom at the same speed regardless of how heavy it is. That's physics being honest with you.
Practice Problem #3: With Friction
Problem: A 3 kg block slides down a rough incline from height 5 m. The work done by friction is 80 J. Find the speed at the bottom.
Solution:
Initial energy: PE = mgh = (3)(9.8)(5) = 147 J
Final energy includes KE minus the energy lost to friction:
PE₁ = KE₂ + W(friction)
147 = ½(3)v² + 80
½(3)v² = 67
1.5v² = 67
v² = 44.67
v = 6.68 m/s
Friction always steals energy. The block gets to the bottom slower than it would on a smooth surface.
Practice Problem #4: The Spring
Problem: A 0.5 kg mass attached to a spring (k = 200 N/m) is compressed 0.2 m and released. What speed does it have when it passes through the equilibrium position?
Solution:
Elastic PE converts to kinetic energy:
½kx² = ½mv²
(200)(0.2)² = (0.5)v²
8 = 0.5v²
v² = 16
v = 4 m/s
Common Mistakes Students Make
- Forgetting to square the velocity — This is the most common error. When you solve for v, you need v² first, then take the square root.
- Mixing up units — Mass in kg, height in meters, velocity in m/s. Everything must be consistent.
- Ignoring friction when it's present — Check the problem statement. If it says "rough surface" or gives a friction value, you must include energy loss.
- Using the wrong height reference — Pick a convenient zero point. Usually the lowest point in the problem works best.
- Solving with kinematics when energy is faster — If you see height and want velocity, energy conservation is almost always the faster route.
How to Solve Any Energy Conservation Problem
Step 1: Identify Your Initial and Final States
What is the object doing at the start? At the end? Write down what you know about velocity and position for each.
Step 2: Choose Your Zero Reference Point
For gravitational PE, pick where h = 0. The ground, the lowest point of a track, wherever makes math easiest.
Step 3: Write the Energy Conservation Equation
Sum of initial energies = sum of final energies. Include every relevant form: kinetic, gravitational PE, elastic PE, and work done by external forces.
Step 4: Plug In What You Know
Substitute values. Leave variables for what you don't know yet.
Step 5: Solve Algebraically
Isolate the unknown. Check that your answer has correct units.
When to Use Energy vs. Forces
Energy conservation works best when:
- You're given heights and need velocities
- The path is complicated (doesn't need to be straight)
- Friction is present and quantified
- Springs or elastic materials are involved
Use kinematics and Newton's laws when:
- You're asked about time
- Acceleration is non-uniform
- Forces are given and you need to find motion
- The problem specifically asks for acceleration
Quick Reference Formulas
Kinetic Energy: KE = ½mv²
Gravitational Potential Energy: PE = mgh
Elastic Potential Energy: PE = ½kx²
Work-Energy Theorem: W = ΔKE
Conservation: KE₁ + PE₁ + W(ext) = KE₂ + PE₂
That's everything you need. Practice the four problems above until you can solve them without looking at the solutions. Energy conservation problems become automatic once you recognize the pattern.