Domain and Range of Composite Functions- Practice Guide

What Are Composite Functions?

A composite function is one function applied to the result of another. If you have f(g(x)), you first calculate g(x), then plug that result into f.

Mathematically, if f: A → B and g: B → C, then the composite fog: A → C maps elements from A through B to C.

The notation matters. (f ∘ g)(x) means f(g(x)). The function on the right gets evaluated first.

Finding the Domain of Composite Functions

The domain isn't just "all x values." You have restrictions from both functions involved.

Step-by-Step Process

Example 1: f(g(x)) where g(x) = √x and f(x) = 1/x

Working through (f ∘ g)(x) = f(√x) = 1/√x:

Example 2: f(g(x)) where g(x) = x² - 4 and f(x) = √x

Working through (f ∘ g)(x) = f(x² - 4) = √(x² - 4):

Finding the Range of Composite Functions

Range is trickier. You need to track what outputs the inner function can produce, then see how the outer function transforms those outputs.

The Process

Example: f(g(x)) where g(x) = 2x + 1 and f(x) = x²

Working through (f ∘ g)(x) = (2x + 1)²:

Practice Problems with Solutions

Problem 1

Find the domain and range of h(x) = √(x² - 9) where h = f ∘ g, g(x) = x² - 9, f(x) = √x.

Solution:

Problem 2

Find the domain and range of h(x) = 1/(x² - 4) where h = f ∘ g, g(x) = x² - 4, f(x) = 1/x.

Solution:

Common Mistakes to Avoid

Domain and Range of Common Function Combinations

Composite TypeDomain ConditionRange Notes
f(g(x)) where f(x) = 1/xg(x) ≠ 0Never produces 0
f(g(x)) where f(x) = √xg(x) ≥ 0Always ≥ 0
f(g(x)) where f(x) = ln(x)g(x) > 0All real numbers possible
f(g(x)) where f(x) = x²Same as g(x)≥ 0 if g's range ⊆ ℝ

Getting Started: Quick Checklist

Before solving any composite function problem:

  1. Identify which function is inner (g) and which is outer (f)
  2. Write out the composite explicitly: f(g(x)) = ?
  3. List domain restrictions for g(x) — solve if needed
  4. List domain restrictions for f(x)
  5. Combine: find x-values satisfying both
  6. For range, find g's range first, then apply f's transformation to that set

When One Function Inverts the Other

If you have f(g(x)) where f and g are inverses, the domain and range simplify significantly.

For (f ∘ f⁻¹)(x) = x:

For (f⁻¹ ∘ f)(x) = x:

This only works when the inner function's outputs stay within the outer function's domain. If g's range exceeds f's domain, the composite isn't defined for those x-values.