Chemical Kinetics- Practice with Solutions
What Is Chemical Kinetics?
Chemical kinetics is the study of reaction ratesβhow fast chemical reactions happen and what affects that speed. That's it. Nothing fancy. You measure rates, you find patterns, you predict behavior.
Most students struggle because they try to memorize everything instead of understanding the relationships. Don't do that. Focus on rate laws, order of reaction, and the Arrhenius equation. Master those three and you've got 80% of the exam covered.
Core Concepts You Need to Know
Rate of Reaction
The rate is the change in concentration over time. For a reaction A β Products:
Rate = β(1/a)(Ξ[A]/Ξt) = (1/b)(Ξ[B]/Ξt)
The negative sign appears because concentration of reactants decreases. Don't forget it when writing rate expressions.
Rate Law and Reaction Order
The rate law tells you how rate depends on concentration:
Rate = k[A]m[B]n
Where:
- k = rate constant
- m = order with respect to A
- n = order with respect to B
- m + n = overall reaction order
Critical point: You cannot determine reaction order from the balanced equation. You get it from experimental data only. Every student forgets this. Don't be that person.
Zero, First, and Second Order Reactions
Each order has distinct characteristics:
- Zero order: Rate is constant, independent of concentration. Half-life depends on initial concentration.
- First order: Rate depends linearly on concentration. Half-life is constant and independent of initial concentration.
- Second order: Rate depends on concentration squared. Half-life increases as concentration decreases.
Key Formulas Reference
| Order | Rate Law | Integrated Law | Half-Life Formula |
|---|---|---|---|
| Zero | Rate = k | [A]t = βkt + [A]0 | t1/2 = [A]0/2k |
| First | Rate = k[A] | ln[A]t = βkt + ln[A]0 | t1/2 = 0.693/k |
| Second | Rate = k[A]2 | 1/[A]t = kt + 1/[A]0 | t1/2 = 1/(k[A]0) |
The Arrhenius Equation
This equation connects temperature and reaction rate:
k = AeβEa/RT
Or in logarithmic form:
ln(k2/k1) = (βEa/R)(1/T2 β 1/T1)
Where:
- A = frequency factor
- Ea = activation energy
- R = 8.314 J/molΒ·K
- T = temperature in Kelvin
Higher temperature or lower activation energy means faster reaction. Simple.
Practice Problems with Solutions
Problem 1: Determining Rate Law from Data
Given: For the reaction 2NO + Cl2 β 2NOCl, the following experimental data was collected:
| Experiment | [NO] (M) | [Cl2] (M) | Initial Rate (M/s) |
|---|---|---|---|
| 1 | 0.10 | 0.10 | 0.018 |
| 2 | 0.20 | 0.10 | 0.072 |
| 3 | 0.10 | 0.20 | 0.036 |
Find: The rate law expression
Solution:
Compare experiments 1 and 2 (Cl2 constant, [NO] doubles):
Rate ratio = 0.072/0.018 = 4
Concentration ratio = 0.20/0.10 = 2
4 = 2m β m = 2 (order with respect to NO is 2)
Compare experiments 1 and 3 ([NO] constant, [Cl2] doubles):
Rate ratio = 0.036/0.018 = 2
Concentration ratio = 0.20/0.10 = 2
2 = 2n β n = 1 (order with respect to Cl2 is 1)
Answer: Rate = k[NO]2[Cl2] β overall order is 3
Problem 2: First Order Kinetics Calculation
Given: The decomposition of N2O5 is first order with k = 4.8 Γ 10β4 sβ1. Initial concentration is 0.80 M.
Find: (a) Half-life, (b) Concentration after 30 minutes
Solution:
(a) Half-life:
t1/2 = 0.693/k = 0.693/(4.8 Γ 10β4) = 1444 s = 24.1 min
(b) Concentration after 30 min (1800 s):
For first order: ln([A]t/[A]0) = βkt
ln([A]t/0.80) = β(4.8 Γ 10β4)(1800)
ln([A]t/0.80) = β0.864
[A]t/0.80 = eβ0.864 = 0.421
[A]t = 0.80 Γ 0.421 = 0.337 M
Problem 3: Arrhenius Equation Application
Given: A reaction has Ea = 85 kJ/mol. The rate constant at 300 K is 2.5 Γ 10β3 sβ1.
Find: Rate constant at 350 K
Solution:
ln(k2/k1) = (βEa/R)(1/T2 β 1/T1)
ln(k2/2.5 Γ 10β3) = (β85000/8.314)(1/350 β 1/300)
ln(k2/2.5 Γ 10β3) = (β10222)(β0.000476)
ln(k2/2.5 Γ 10β3) = 4.87
k2/2.5 Γ 10β3 = e4.87 = 130.6
k2 = 130.6 Γ 2.5 Γ 10β3 = 0.327 sβ1
Problem 4: Determining Order and Half-Life
Given: For a reaction A β products, the following data was collected:
| Time (min) | [A] (M) |
|---|---|
| 0 | 0.50 |
| 10 | 0.35 |
| 20 | 0.25 |
| 30 | 0.18 |
Find: (a) Is the reaction zero, first, or second order? (b) Calculate the rate constant
Solution:
Test each order by checking for linearity:
Zero order test: [A] vs time should be linear
Ξ[A]/Ξt = (0.35 β 0.50)/10 = β0.015 M/min (not constant)
First order test: ln[A] vs time should be linear
ln(0.35) = β1.05, ln(0.25) = β1.39, ln(0.18) = β1.71
Plot looks linear β First order
Rate constant:
Using two points: ln([A]t/[A]0) = βkt
ln(0.35/0.50) = βk(10)
β0.357 = β10k
k = 0.0357 minβ1
Half-life = 0.693/0.0357 = 19.4 minutes
Common Mistakes Students Make
- Solving rate from stoichiometry: Wrong. Rate comes from experiment, not from the balanced equation.
- Forgetting units: k units change with reaction order. Always check your units match expected values.
- Confusing half-life formulas: First order half-life is constant. Zero and second order half-lives depend on initial concentration.
- Temperature in Celsius: Must convert to Kelvin for Arrhenius calculations.
- Not checking linearity: Always verify the order by testing which graph gives a straight line.
Quick Study Guide
If you're cramming before an exam, memorize this checklist:
- Rate law format: Rate = k[A]m[B]n
- Reaction order comes from experiment only
- First order half-life: t1/2 = 0.693/k (constant!)
- For first order graphs: plot ln[A] vs time β straight line
- For second order graphs: plot 1/[A] vs time β straight line
- Arrhenius: higher T or lower Ea = faster reaction
- Units of k: M1βordersβ1
That's chemical kinetics. No fluff, just the math and the logic. Work through the practice problems until you can solve them without looking at the solutions.