Bond Order of O2-- Superoxide Ion Explained

What Is the Bond Order of O₂⁻ (Superoxide Ion)?

The bond order of the superoxide ion (O₂⁻) is 1.5. That's the short answer. But if you're studying chemistry, you need to understand why it's 1.5 and how molecular orbital theory gives us this number. Keep reading.

Molecular Orbital Theory Basics

Before calculating bond order, you need to know how oxygen's molecular orbitals fill up. O₂ has 16 total electrons (8 from each oxygen). When you fill the molecular orbitals according to energy levels, you get a specific electron configuration.

The molecular orbital order for diatomic oxygen (from lowest to highest energy):

Calculating Bond Order of O₂⁻

The bond order formula is simple:

Bond Order = (Bonding electrons - Antibonding electrons) ÷ 2

O₂ has 16 electrons total. O₂⁻ (superoxide) has one extra electron, making it 17 electrons.

Here's how the electrons fill up:

Counting bonding vs antibonding electrons:

Bond Order = (12 - 7) ÷ 2 = 5 ÷ 2 = 1.5

Oxygen Species Comparison

This table shows how superoxide compares to other oxygen species:

Species Total Electrons Bond Order Bond Length (pm) Magnetic Property
O₂ (dioxygen) 16 2 121 Paramagnetic
O₂⁻ (superoxide) 17 1.5 134 Paramagnetic
O₂²⁻ (peroxide) 18 1 149 Diamagnetic
O₂⁺ (dioxygenyl) 15 2.5 112 Paramagnetic

Notice the pattern: as electrons get added to antibonding orbitals, bond order drops and bond length increases. O₂⁻ sits right in the middle with a bond order of 1.5.

Why Bond Order Matters

A bond order of 1.5 means the bond is stronger than a single bond but weaker than a double bond. This has real consequences:

Where Superoxide Appears

Superoxide isn't just a textbook example. It shows up in real systems:

Quick Reference

If you need to remember one thing: bond order of 1.5. Everything else about superoxide — its reactivity, its properties, its biological role — flows directly from that number.