Solving Rational Inequalities- Practice Problems with Solutions
What Are Rational Inequalities?
A rational inequality is an inequality that contains a rational expression—basically a fraction where the numerator and denominator are polynomials. You're asked to find the values of the variable that make the inequality true.
The standard forms look like this:
- R(x) < 0 or R(x) > 0
- R(x) ≤ 0 or R(x) ≥ 0
Where R(x) is some rational expression like (x+2)/(x-3) or (x²-4)/(x+1).
The Critical Rule Most People Forget
Never multiply both sides by the denominator unless you know its sign. This is where students consistently make mistakes.
When you multiply by a negative number, the inequality sign flips. When you multiply by a positive number, it stays the same. Since the denominator changes sign at its zeros, guessing is not an option.
How to Solve Rational Inequalities
Step 1: Move Everything to One Side
Get zero on one side of the inequality. Your expression should look like:
R(x) < 0 or R(x) > 0
Step 2: Find the Critical Points
Critical points come from two sources:
- Zeros of the numerator (where the expression equals zero)
- Zeros of the denominator (where the expression is undefined)
Step 3: Plot on a Number Line
Mark these critical points on a number line. Use open circles for points that make the denominator zero (never included in the solution). Use closed circles for points that make the numerator zero (included when the inequality is ≥ or ≤).
Step 4: Test the Intervals
Pick a test value from each interval created by your critical points. Plug it into the simplified expression. Check if the result is positive or negative.
Step 5: Write the Solution
Based on your inequality sign, select the intervals that satisfy the condition. Combine with the appropriate critical points.
Practice Problems with Solutions
Problem 1: Basic Case
Solve: (x-2)/(x+3) > 0
Step 1: Already in correct form.
Step 2: Critical points are x = 2 (numerator) and x = -3 (denominator).
Step 3: Number line with points at -3 and 2.
Step 4: Test intervals:
- Test x = -4: (-4-2)/(-4+3) = (-6)/(-1) = 6 > 0 ✓
- Test x = 0: (0-2)/(0+3) = -2/3 < 0 ✗
- Test x = 3: (3-2)/(3+3) = 1/6 > 0 ✓
Solution: x < -3 or x > 2
Write it in interval notation: (-∞, -3) ∪ (2, ∞)
Problem 2: Including the Zero
Solve: (x+1)/(x-4) ≤ 0
Critical points: x = -1 and x = 4
Test intervals:
- Test x = -2: (-2+1)/(-2-4) = (-1)/(-6) > 0 ✗
- Test x = 0: (0+1)/(0-4) = 1/(-4) < 0 ✓
- Test x = 5: (5+1)/(5-4) = 6/1 > 0 ✗
Solution: -1 ≤ x < 4
Interval notation: [-1, 4)
The x = -1 is included because the inequality is ≤ and the numerator equals zero makes the whole expression zero. The x = 4 is excluded because the denominator is zero.
Problem 3: Factored Numerator
Solve: (x² - 9)/(x + 2) < 0
Factor: ((x-3)(x+3))/(x+2) < 0
Critical points: x = -3, x = 3, x = -2
Test intervals:
- Test x = -4: ((-4)²-9)/(-4+2) = (16-9)/(-2) = 7/(-2) < 0 ✓
- Test x = -2.5: ((-2.5)²-9)/(-2.5+2) = (6.25-9)/(-0.5) = (-2.75)/(-0.5) > 0 ✗
- Test x = 0: ((0)²-9)/(0+2) = -9/2 < 0 ✓
- Test x = 4: ((4)²-9)/(4+2) = (16-9)/6 = 7/6 > 0 ✗
Solution: x < -3 or -2 < x < 3
Interval notation: (-∞, -3) ∪ (-2, 3)
Problem 4: Quadratic in Denominator
Solve: (x + 2)/(x² - 4) ≥ 0
Factor denominator: (x + 2)/((x-2)(x+2)) ≥ 0
Simplify: Cancel the common factor (x + 2), but remember x ≠ -2 from the original denominator.
Critical points: x = 2 (from denominator), x = -2 (from original denominator)
After simplification to 1/(x-2):
Test:
- Test x = 0: 1/(0-2) = -1/2 < 0 ✗
- Test x = 3: 1/(3-2) = 1 > 0 ✓
Solution: x > 2
Interval notation: (2, ∞)
The x = -2 is excluded because it made the denominator zero in the original expression. No values satisfy the ≥ 0 condition at the critical points.
Common Mistakes to Avoid
- Multiplying by the denominator without checking its sign first. This is the fastest way to get the wrong answer.
- Forgetting to exclude denominator zeros. These are never part of your solution, no matter what.
- Including numerator zeros when the inequality is strict (< or >). Only include them when the inequality is ≤ or ≥.
- Simplifying incorrectly. If you cancel factors, note any restrictions they introduce.
Quick Reference Table
| Inequality | When Numerator = 0 | When Denominator = 0 |
|---|---|---|
| R(x) > 0 | Not included (value is 0) | Never included |
| R(x) < 0 | Not included (value is 0) | Never included |
| R(x) ≥ 0 | Included (value is 0) | Never included |
| R(x) ≤ 0 | Included (value is 0) | Never included |
Getting Started: Your Checklist
Before you start solving any rational inequality, run through this:
- ☐ Is everything on one side with zero on the other?
- ☐ Did you factor numerator and denominator completely?
- ☐ Did you find all critical points (numerator = 0 AND denominator = 0)?
- ☐ Did you mark denominator zeros with open circles?
- ☐ Did you test at least one point in each interval?
- ☐ Did you check whether numerator zeros are included?
- ☐ Did you write the answer in interval notation?
If you answered yes to all of these, your solution is solid.
When to Use a Sign Chart
A sign chart is the fastest method for rational inequalities with multiple factors. Instead of testing every interval with numbers, you track the sign of each factor.
For (x+2)(x-3)/(x+1) > 0:
- Critical points: -2, -1, 3
- Sign of (x+2): negative left of -2, positive right
- Sign of (x-3): negative left of 3, positive right
- Sign of (x+1): negative left of -1, positive right
- Multiply the signs in each interval
This method gets fast with practice. It's the technique you'll use on timed tests.