SN2 vs SNA vs E1 vs E2- Reaction Mechanisms Compared
SN1 vs SN2 vs E1 vs E2: What You Actually Need to Know
If you're taking organic chemistry, you've probably stared at a reaction and had no idea whether it'll go SN1, SN2, E1, or E2. That's normal. Most students do. The good news is these four mechanisms follow predictable rules. Learn the patterns, and you'll stop guessing.
These are the four major reaction mechanisms you'll encounter for alkyl halides and similar substrates. Each one has specific conditions that favor it. Get those conditions down, and you can predict products without memorizing everything.
SN2: Bimolecular Nucleophilic Substitution
SN2 reactions involve a single step where the nucleophile attacks the electrophile at the same time the leaving group leaves. It's a backside attack, which means stereochemistry inverts—like an umbrella flipping inside out in the wind.
Key Characteristics of SN2
- Single concerted step
- Stereochemistry inverts (Walden inversion)
- Rate depends on both substrate AND nucleophile (second-order kinetics)
- Works best with methyl, primary, and secondary substrates
- Tertiary substrates basically don't do SN2—steric hindrance blocks the attack
The nucleophile must physically reach the carbon bearing the leaving group. If there are three bulky groups in the way, it's not happening. That's why methyl halides react fastest, followed by primary, then secondary. Tertiary? Forget it.
Good Nucleophiles for SN2
You need strong nucleophiles for SN2. Charge helps—negatively charged species are better than neutral ones. Some reliable ones:
- Iodide (I⁻)
- Bromide (Br⁻)
- Cyanide (CN⁻)
- Acetate (CH₃COO⁻)
- Alcohols (in some cases)
Weak nucleophiles like water or alcohols won't drive SN2. They'll sit around waiting for something else to happen.
SN1: Unimolecular Nucleophilic Substitution
SN1 reactions happen in two steps. First, the leaving group leaves on its own, forming a flat carbocation intermediate. Then the nucleophile attacks from either side of that carbocation.
Key Characteristics of SN1
- Two distinct steps
- Carbocation intermediate forms
- Rate depends only on substrate (first-order kinetics)
- Tertiary carbocations are stable—tertiary substrates love SN1
- Stereochemistry gives a racemic mixture (or at least partial racemization)
Because the carbocation is planar, the nucleophile can attack from either face. If you start with a single enantiomer, you get both R and S products. That's racemization.
When SN1 Dominates
SN1 wins when:
- The substrate is tertiary or allylic (stabilized carbocation)
- A good leaving group is present
- The nucleophile is weak (doesn't matter if it attacks slowly)
- A polar protic solvent stabilizes the carbocation
Polar protic solvents like water or alcohols actually help SN1 by solvating and stabilizing the charged intermediate. That's the opposite of SN2, where these solvents slow things down by hydrogen-bonding to the nucleophile.
E2: Bimolecular Elimination
E2 is elimination, meaning you're removing a hydrogen and a leaving group to form a double bond. Like SN2, it's a single concerted step. The base pulls off the hydrogen at the same time the leaving group departs.
Key Characteristics of E2
- Single step, concerted mechanism
- Rate depends on both substrate and base (second-order kinetics)
- Requires anti-periplanar geometry—the H and leaving group must be on opposite sides
- Strong bases drive E2
- Zaitsev's Rule applies—more substituted alkene usually forms
The anti-periplanar requirement matters. If the hydrogen and leaving group can't get opposite each other due to ring strain or sterics, E2 won't happen easily. Cyclohexane rings in particular lock in anti-periplanar geometry for axial substituents.
Strong Bases for E2
- Hydroxide (OH⁻)
- Alkoxides (RO⁻)
- Amides (NH₂⁻)
- Grignard reagents (in some contexts)
These bases are strong enough to rip a proton off while the leaving group exits. Weaker bases can't keep up with the timing.
E1: Unimolecular Elimination
E1 follows the same first two steps as SN1—leaving group leaves, carbocation forms. Then instead of a nucleophile attacking, a base removes a proton from a carbon adjacent to the carbocation, forming the double bond.
Key Characteristics of E1
- Two steps with carbocation intermediate
- Rate depends only on substrate (first-order kinetics)
- Same carbocation rearrangement possibilities as SN1
- Weak bases or base concentrations favor E1 over E2
- Zaitsev's Rule applies
Because the carbocation can lose a proton from different carbons, you often get mixtures of alkene products. The more substituted double bond usually predominates, but you're not guaranteed a single product.
E1 vs SN1: Same Starting Point, Different Outcome
After the carbocation forms, it either:
- Gets attacked by a nucleophile → SN1
- Loses a proton to form a double bond → E1
The nucleophile versus base competition determines which pathway dominates. Strong nucleophiles favor SN1. Weak nucleophiles with strong bases favor E1.
Side-by-Side Comparison
| Feature | SN2 | SN1 | E2 | E1 |
|---|---|---|---|---|
| Steps | One | Two | One | Two |
| Kinetics | Second-order | First-order | Second-order | First-order |
| Rate depends on | Substrate + nucleophile | Substrate only | Substrate + base | Substrate only |
| Stereochemistry | Inversion | Racemization | Anti-periplanar required | No stereochemical preference |
| Best substrate | Methyl, 1°, 2° | 3°, allylic | Unhindered 2°, 3° | 3°, allylic |
| Leaving group | Must be good | Must be good | Must be good | Must be good |
| Base/nucleophile strength | Strong nucleophile needed | Weak nucleophile OK | Strong base needed | Weak base OK |
| Solvent effect | Polar aprotic speeds it up | Polar protic stabilizes carbocation | No strong preference | Polar protic helps |
How to Predict Which Mechanism Occurs
Here's the decision tree that actually works on exams:
Step 1: Check the Substrate
Tertiary substrate? → Elimination wins (E1 or E2). SN2 is impossible. SN1 is possible but elimination usually dominates with strong bases.
Primary substrate? → SN2 is your main option. E2 is possible with a very strong base, but SN2 usually wins unless the base is huge (like t-butoxide).
Secondary substrate? → This is where it gets complicated. You need to look at other factors.
Step 2: Check the Reagent
Strong nucleophile AND strong base? → SN2 or E2 (depending on substrate). If it's also bulky, E2 wins even at secondary carbons.
Weak nucleophile, weak base? → SN1 or E1 (carbocation pathway). Which one actually happens depends on what else is present.
Strong nucleophile, weak base? → SN2. The nucleophile attacks before elimination can happen.
Step 3: Check the Solvent
Polar aprotic solvent (acetone, DMSO, DMF) → SN2 or E2. These solvents don't stabilize the nucleophile, so it's more reactive.
Polar protic solvent (water, alcohols) → SN1 or E1. These stabilize carbocations and slow down anions.
The Quick Rules
- SN2: Methyl or primary carbon + strong nucleophile + polar aprotic solvent
- SN1: Tertiary carbon + good leaving group + polar protic solvent
- E2: Strong base + anti-periplanar hydrogen + substrate can form alkene
- E1: Tertiary carbon + weak base + polar protic solvent
Getting Started: Working Through a Problem
Say you see 2-bromopropane reacting with hydroxide. How do you figure out what happens?
1. Identify the substrate. 2-bromopropane is secondary. That rules out SN1 (tertiary only) and makes SN2 unlikely but possible.
2. Identify the reagent. Hydroxide is both a strong nucleophile and a strong base. That's your clue.
3. Check conditions. If this is in water (polar protic), SN1/E1 becomes more likely. In an alcohol solvent, similar. In DMSO (polar aprotic), SN2/E2 dominates.
4. Make your call. With hydroxide and a secondary substrate in polar aprotic solvent, you'll get mostly SN2 with some E2. In polar protic, you'll get a mixture of SN1, E1, and E2—probably elimination products dominate.
This is why exam questions always specify conditions. Change the solvent, change the product distribution.
Carbocation Rearrangements
Both SN1 and E1 involve carbocations. Those carbocations can rearrange—a hydrogen or methyl group shifts to form a more stable carbocation. When that happens, your product reflects the rearranged structure, not the original.
You'll know rearrangement happened if the carbon skeleton of your product doesn't match the starting material. Watch for this on exams. If you draw a product and the carbon chain looks different, you probably had a rearrangement.
What About Competing Pathways?
In the real world, reactions don't give you one clean product. You get mixtures. A secondary substrate with a moderate base might give you SN2 product, E2 product, and maybe some SN1 if conditions allow. That's normal.
Your job isn't to predict a single product—it's to predict the major product and explain why. Focus on the factors that favor one pathway over others. The substrate is usually the biggest factor, followed by the reagent strength.
The Bottom Line
SN1 and SN1 differ in steps, stereochemistry, and what controls the rate. E1 and E2 are elimination counterparts with similar distinctions. The patterns are consistent:
- One-step reactions (SN2, E2) depend on both reactants—second-order kinetics
- Two-step reactions (SN1, E1) go through carbocations—first-order kinetics, rearrangements possible
- Steric bulk of the substrate determines whether substitution or elimination wins
- Reagent strength determines which pathway within substitution or elimination
Once you internalize these patterns, you stop having to guess. You just read the conditions and the mechanism follows.